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Putting It All Together
The previous sections described how to construct the try,
catch, and finally code blocks for
the writeList method in the ListOfNumbers class.
Now, let's walk through the code and investigate what can happen.
When all the components are put together, the writeList
method looks like the following.
public void writeList() {
PrintWriter out = null;
try {
System.out.println("Entering try statement");
out = new PrintWriter(
new FileWriter("OutFile.txt"));
for (int i = 0; i < SIZE; i++)
out.println("Value at: " + i + " = "
+ vector.elementAt(i));
} catch (ArrayIndexOutOfBoundsException e) {
System.err.println("Caught "
+ "ArrayIndexOutOfBoundsException: "
+ e.getMessage());
} catch (IOException e) {
System.err.println("Caught IOException: "
+ e.getMessage());
} finally {
if (out != null) {
System.out.println("Closing PrintWriter");
out.close();
}
else {
System.out.println("PrintWriter not open");
}
}
}
As mentioned previously, this method's try block
has three different exit possibilities; here are two of them.
-
Code in the
try statement fails and throws an exception.
This could be an IOException caused by the new
FileWriter statement or an
ArrayIndexOutOfBoundsException caused by a wrong index
value in the for loop.
-
Everything succeeds and the
try statement exits normally.
Let's look at what happens in the writeList method
during these two exit possibilities.
Scenario 1: An Exception Occurs
The statement that creates a FileWriter can fail
for a number of reasons. For example, the constructor for the
FileWriter throws an IOException
if the program cannot create or write to the file indicated.
When FileWriter throws an IOException,
the runtime system immediately stops executing the try block; method calls being executed are not completed. The runtime system then starts searching at the top of the method call stack for an appropriate exception handler. In this example, when the IOException occurs, the FileWriter constructor is at the top of the call stack. However, the FileWriter constructor doesn't have an appropriate exception handler, so the runtime system checks the next method — the writeList method — in the method call stack. The writeList
method has two exception handlers: one for IOException
and one for ArrayIndexOutOfBoundsException.
The runtime system checks writeList's handlers in the order
in which they appear after the try statement. The argument
to the first exception handler is ArrayIndexOutOfBoundsException. This does not match the type of exception thrown, so the runtime system checks the next exception handler — IOException. This matches the type of exception that was thrown, so the runtime system ends its search for an appropriate exception handler. Now that the runtime has found an appropriate handler, the code in that catch block is executed.
After the exception handler executes, the runtime system passes
control to the finally block. Code in the finally block executes regardless of the exception caught above it. In this scenario, the FileWriter was never opened and doesn't need to be
closed. After the finally block finishes executing,
the program continues with the first statement after the finally block.
Here's the complete output from the ListOfNumbers program that appears when an IOException is thrown.
Entering try statement
Caught IOException: OutFile.txt
PrintWriter not open
The boldface code in the following listing shows the statements
that get executed during this scenario:
public void writeList() {
PrintWriter out = null;
try {
System.out.println("Entering try statement");
out = new PrintWriter(
new FileWriter("OutFile.txt"));
for (int i = 0; i < SIZE; i++)
out.println("Value at: " + i
+ " = " + vector.elementAt(i));
} catch (ArrayIndexOutOfBoundsException e) {
System.err.println("Caught "
+ "ArrayIndexOutOfBoundsException: "
+ e.getMessage());
} catch (IOException e) {
System.err.println("Caught IOException: "
+ e.getMessage());
} finally {
if (out != null) {
System.out.println("Closing PrintWriter");
out.close();
}
else {
System.out.println("PrintWriter not open");
}
}
}
Scenario 2: The try Block Exits Normally
In this scenario, all the statements within the scope of the try
block execute successfully and throw no exceptions. Execution falls off the
end of the try block, and the runtime system passes control
to the finally block. Because everything was successful, the
PrintWriter is open when control reaches the finally
block, which closes the PrintWriter. Again, after the
finally block finishes executing, the program continues
with the first statement after the finally block.
Here is the output from the ListOfNumbers program when no exceptions are thrown.
Entering try statement
Closing PrintWriter
The boldface code in the following sample shows the statements that
get executed during this scenario.
public void writeList() {
PrintWriter out = null;
try {
System.out.println("Entering try statement");
out = new PrintWriter(
new FileWriter("OutFile.txt"));
for (int i = 0; i < SIZE; i++)
out.println("Value at: " + i + " = "
+ vector.elementAt(i));
} catch (ArrayIndexOutOfBoundsException e) {
System.err.println("Caught "
+ "ArrayIndexOutOfBoundsException: "
+ e.getMessage());
} catch (IOException e) {
System.err.println("Caught IOException: "
+ e.getMessage());
} finally {
if (out != null) {
System.out.println("Closing PrintWriter");
out.close();
}
else {
System.out.println("PrintWriter not open");
}
}
}